#Nodus launcher please select a version windows#
The Windows documentation says that The py.exe launcher will automatically select the most recent version of Python you've installed, so I reinstalled Python 3.6 (after having already installed Python 3.9) but, still the default is set to Python 3.9 when I open a file with C:\WINDOWS\py.exe I have set another environment variable PY_PYTHON to PY_PYTHON=3.6.
In path, I have move C:\Users\user\AppData\Local\Programs\Python\Python36\ above C:\Users\user\AppData\Local\Programs\Python\Python39. I have created a C:\Windows\py.ini with the default set to python=3.6 (same for pyw). default to C:\Windows\py.exe but if I do that my scripts are open in Python 3.9.5 and so they failed. For my scripts that need to use Python 3.9, I use the shebang #! python3.9. I haven't yet updated all the package to Python 3.9 so I want the default Python to be 3.6. I was running on Python 3.6 only until I installed Python 3.9 along side. py' to C:\Windows\py.exe, then if they don't have a sheband they will be started with Python 3.6.5`? How can I make sure that if I set open all. When I type py in a CMD I get Python 3.6.5.īut if I double click on C:\Windows\py.exe the console is Python 3.9.5. When I right click on a file, choose open with and select C:\Windows\py.exe, then by default (without any shebang), it's Python 3.9 that is open. Python 3.9 should only be used for files with a shebang #! python3.9 I want the default version of the Python launcher for Windows to be Python 3.6 so that the files without a shebang are open with Python 3.6. pyw (ex: when I double click on them) with Python Launcher for Windows. I have two versions of Python installed: Python 3.6 and Python 3.9.
0 kommentar(er)
